document.write( "Question 143822: a sltwater solution of 40 cups is 30%salt.Approximately how many cups of another saltwater solution of 65% salt mixture need to be added to obtain a 50% salt solution ? \n" ); document.write( "

Algebra.Com's Answer #104655 by ptaylor(2198) $\"\"$ $\"About$

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\n" ); document.write( "Let x=amount of 65% solution needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure salt in the 30% solution (0.30*40) plus the amount of pure salt in the 65% solution (0.65x) has to equal the amount of pure salt in the final mixture (0.50(40+x)). So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.30*40+0.65x=0.50(40+x) get rid of parens (distributive law)\r
\n" ); document.write( "\n" ); document.write( "12+0.65x=20+0.50x subtract 0.50x and also 12 from each side\r
\n" ); document.write( "\n" ); document.write( "12-12+0.65x-0.50x=20-12+0.50x-0.50x collect like terms\r
\n" ); document.write( "\n" ); document.write( "0.15x=8 divide each side by 0.15\r
\n" ); document.write( "\n" ); document.write( "x=53 1/3 cups or approximately 53 cups-----------ans\r
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\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "0.30*40+0.65*53=0.50*93\r
\n" ); document.write( "\n" ); document.write( "12+34.45=46.5
\n" ); document.write( "46.45~~~~~~~~~~~~~~~~~~~46.5\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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