document.write( "Question 143785: Solve the following system of equations for the unknown variables.
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document.write( "3x + 3y = 3
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document.write( "-3x – 2z = -11
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document.write( "y + z = -1
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Algebra.Com's Answer #104640 by nabla(475)![]() ![]() ![]() You can put this solution on YOUR website! I'm going to solve this with matrices. You could solve this through substitution among other methods as well... \n" ); document.write( "3 3 0 3 \n" ); document.write( "-3 0 -2 -11 \n" ); document.write( "0 1 1 -1\r \n" ); document.write( "\n" ); document.write( "R1+R2--->\r \n" ); document.write( "\n" ); document.write( "3 3 0 3 \n" ); document.write( "0 3 -2 -8 \n" ); document.write( "0 1 1 -1\r \n" ); document.write( "\n" ); document.write( "1/3R1--->\r \n" ); document.write( "\n" ); document.write( "1 1 0 1 \n" ); document.write( "0 3 -2 -8 \n" ); document.write( "0 1 1 -1\r \n" ); document.write( "\n" ); document.write( "1/3R2--> \n" ); document.write( "1 1 0 1 \n" ); document.write( "0 1 -2/3 -8/3 \n" ); document.write( "0 1 1 -1\r \n" ); document.write( "\n" ); document.write( "-R2+R3--> \n" ); document.write( "1 1 0 1 \n" ); document.write( "0 1 -2/3 -8/3 \n" ); document.write( "0 0 5/3 5/3\r \n" ); document.write( "\n" ); document.write( "-R2+R1--> \n" ); document.write( "1 0 2/3 11/3 \n" ); document.write( "0 1 -2/3 -8/3 \n" ); document.write( "0 0 5/3 5/3\r \n" ); document.write( "\n" ); document.write( "3/5R3--> \n" ); document.write( "1 0 2/3 11/3 \n" ); document.write( "0 1 -2/3 -8/3 \n" ); document.write( "0 0 1 1\r \n" ); document.write( "\n" ); document.write( "2/3R3+R2--> \n" ); document.write( "1 0 2/3 11/3 \n" ); document.write( "0 1 0 -2 \n" ); document.write( "0 0 1 1\r \n" ); document.write( "\n" ); document.write( "-2/3R3+R1--> \n" ); document.write( "1 0 0 3 \n" ); document.write( "0 1 0 -2 \n" ); document.write( "0 0 1 1\r \n" ); document.write( "\n" ); document.write( "We can now read off the solution set: \n" ); document.write( "{3,-2,1}. \n" ); document.write( "check: \n" ); document.write( "3(3) + 3(-2) = 9-6=3 \n" ); document.write( "-3(3) – 2(1) = -9-2=-11 \n" ); document.write( "-2 + 1 = -1 \n" ); document.write( " \n" ); document.write( " |