document.write( "Question 143724: 2. Solve \"x%2B3%2Asqrt%28x%29-40=0\"\r
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Algebra.Com's Answer #104588 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%2B3%2Asqrt%28x%29-40=0\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "Let \"y=sqrt%28x%29\". So \"y%5E2=%28sqrt%28x%29%29%5E2=x\". In other words, \"y%5E2=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2%2B3y-40=0\" Replace \"sqrt%28x%29\" with y and replace x with \"y%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B8%29%28y-5%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"y%2B8=0\" or \"y-5=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"y=-8\" or \"y=5\" Now solve for y in each case\r
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\n" ); document.write( "\n" ); document.write( "So the y values are \r
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\n" ); document.write( "\n" ); document.write( " \"y=-8\" or \"y=5\" \r
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\n" ); document.write( "\n" ); document.write( "Remember, we let \"y=sqrt%28x%29\". \r
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\n" ); document.write( "\n" ); document.write( "\"-8=sqrt%28x%29\" Plug in \"y=-8\" \r
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\n" ); document.write( "\n" ); document.write( "\"%28-8%29%5E2=x\" Square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"64=x\" Square -8 to get 64\r
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\n" ); document.write( "\n" ); document.write( "So the first possible answer is \"x=64\". But we need to check our answer\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B3%2Asqrt%28x%29-40=0\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"64%2B3%2Asqrt%2864%29-40=0\" Plug in \"x=64\"\r
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\n" ); document.write( "\n" ); document.write( "\"64%2B3%2A8-40=0\" Take the square root of 64 to get 8\r
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\n" ); document.write( "\n" ); document.write( "\"64%2B24-40=0\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"48=0\" Combine like terms. Since this is not true, this means that \"x=64\" is not a solution\r
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\n" ); document.write( "\n" ); document.write( "\"5=sqrt%28x%29\" Now plug in \"y=5\" (this is the other y-value we found previously)\r
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\n" ); document.write( "\n" ); document.write( "\"%285%29%5E2=x\" Square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"25=x\" Square 5 to get 25\r
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\n" ); document.write( "\n" ); document.write( "So the second possible answer is \"x=25\". But we need to check our answer\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B3%2Asqrt%28x%29-40=0\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"25%2B3%2Asqrt%2825%29-40=0\" Plug in \"x=25\"\r
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\n" ); document.write( "\n" ); document.write( "\"25%2B3%2A5-40=0\" Take the square root of 25 to get 5\r
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\n" ); document.write( "\n" ); document.write( "\"25%2B15-40=0\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"0=0\" Combine like terms. Since this is true, this means that \"x=25\" is a solution\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=25\"
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