document.write( "Question 143708: Let f(x) = -x^3 + 3x^2 - 3x + 1, and g(x) be f(x) divided by 1 - x; solve for
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document.write( "g(x) if 1 -x is a factor or f(x).\r
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document.write( "a. g(x) = x^4 - 4x^3 + 6x^2 - 4x + 1
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document.write( "b. g(x) = x^3 - 3x^2 + 3x -1
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document.write( "c. g(x) = -x^2 + 2x - 1
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document.write( "d. g(x) = x^2 - 2x + 1 \n" );
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Algebra.Com's Answer #104576 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! Let f(x) = -x^3 + 3x^2 - 3x + 1, and g(x) be f(x) divided by 1 - x; solve for \n" ); document.write( "g(x) if 1 -x is a factor or f(x). \n" ); document.write( "a. g(x) = x^4 - 4x^3 + 6x^2 - 4x + 1 \n" ); document.write( "b. g(x) = x^3 - 3x^2 + 3x -1 \n" ); document.write( "c. g(x) = -x^2 + 2x - 1 \n" ); document.write( "d. g(x) = x^2 - 2x + 1 \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Write 1 - x as -x + 1 and divide by \r\n" ); document.write( "long division to find g(x):\r\n" ); document.write( "\r\n" ); document.write( " x² - 2x + 1\r\n" ); document.write( " ------------------- \r\n" ); document.write( "-x + 1)-x³ + 3x² - 3x + 1\r\n" ); document.write( " -x³ + x²\r\n" ); document.write( " ---------\r\n" ); document.write( " 2x² - 3x\r\n" ); document.write( " 2x² - 2x\r\n" ); document.write( " --------\r\n" ); document.write( " -x + 1\r\n" ); document.write( " -x + 1\r\n" ); document.write( " ------\r\n" ); document.write( " 0\r\n" ); document.write( "\r\n" ); document.write( "So g(x) = x² - 2x + 1, which is \r\n" ); document.write( "choice d.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |