document.write( "Question 21688: Find three consecutive odd integers such that the product of three and the third integer is twenty-one more than two times the sum of the first two numbers.\r
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Algebra.Com's Answer #10456 by Paul(988)\"\" \"About 
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First = x
\n" ); document.write( "second = x+2
\n" ); document.write( "third = x+4
\n" ); document.write( "3(x+4)=21+2(x+x+2)
\n" ); document.write( "3x+12=21+4x+4
\n" ); document.write( "3x+12=25+4x
\n" ); document.write( "x=-13
\n" ); document.write( "-13+2=-11
\n" ); document.write( "-13+4=-9
\n" ); document.write( "Hence, the three consective numbers are -13, -11, and -9
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