document.write( "Question 21688: Find three consecutive odd integers such that the product of three and the third integer is twenty-one more than two times the sum of the first two numbers.\r
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Algebra.Com's Answer #10456 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! First = x \n" ); document.write( "second = x+2 \n" ); document.write( "third = x+4 \n" ); document.write( "3(x+4)=21+2(x+x+2) \n" ); document.write( "3x+12=21+4x+4 \n" ); document.write( "3x+12=25+4x \n" ); document.write( "x=-13 \n" ); document.write( "-13+2=-11 \n" ); document.write( "-13+4=-9 \n" ); document.write( "Hence, the three consective numbers are -13, -11, and -9 \n" ); document.write( " |