document.write( "Question 143652: if two friends leave from the same place traveling to a destination of 720 miles away, and one leaves 2 hours before the other traveling at a rate of 60 miles an hour and the other leaves traveling at a rate of 80 miles an hour, at what time would they pass eachother on the road? \n" ); document.write( "
Algebra.Com's Answer #104549 by ankor@dixie-net.com(22740)\"\" \"About 
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if two friends leave from the same place traveling to a destination of 720 miles away, and one leaves 2 hours before the other traveling at a rate of 60 miles an hour and the other leaves traveling at a rate of 80 miles an hour, at what time would they pass each other on the road?
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\n" ); document.write( "The destination distance is irrelevant, as long as it is greater than the
\n" ); document.write( " distance where one passes the other
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\n" ); document.write( "Let t = travel time of the 1st person
\n" ); document.write( "then
\n" ); document.write( "(t-2) = travel time of the 2nd person
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\n" ); document.write( "We know when 1 passes the other, they will have traveled the same distance
\n" ); document.write( "Write a distance equation: Dist speed * time
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\n" ); document.write( "2nd person dist = 1st person dist
\n" ); document.write( "80(t-2) = 60t
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\n" ); document.write( "80t - 160 = 60t
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\n" ); document.write( "80t - 60t = +160
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\n" ); document.write( "20t = 160
\n" ); document.write( "t = \"160%2F20\"
\n" ); document.write( "t = 8 hrs from the time the 1st person starts or 6 hrs after the 2nd person starts:
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\n" ); document.write( "Check by finding the distances:
\n" ); document.write( "60*8 = 480
\n" ); document.write( "80*6 = 480 \n" ); document.write( "
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