document.write( "Question 143652: if two friends leave from the same place traveling to a destination of 720 miles away, and one leaves 2 hours before the other traveling at a rate of 60 miles an hour and the other leaves traveling at a rate of 80 miles an hour, at what time would they pass eachother on the road? \n" ); document.write( "
Algebra.Com's Answer #104544 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Imagine you have a stopwatch. Start the stopwatch the instant \n" ); document.write( "the 2nd friend leaves. Then ask: \"where is the 1st one at that time?\" \n" ); document.write( "He has gone \n" ); document.write( "When will they pass eachother? \n" ); document.write( "Call the distance the 1st one has to go \n" ); document.write( "Then the distance the 2nd one has to go will be \n" ); document.write( "The stopwatch will show the same time for both when they meet \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "They will meet in 6 hours \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |