document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143591>Question 143591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the lenght of a rectangle is 4 feet less than twice the width. the perimeter is 28 feet. find the length and width fo the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104522 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter is the sum of all the sides.\r<BR>\n" );
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document.write( "Let w be the width.<BR>\n" );
document.write( "L = 2w-4\r<BR>\n" );
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document.write( "P = w + l + w + l<BR>\n" );
document.write( "28 = w + 2w -4 + w + 2w -4<BR>\n" );
document.write( "28 = 6w - 8<BR>\n" );
document.write( "36 = 6w<BR>\n" );
document.write( "6 = w\r<BR>\n" );
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document.write( "l = 12 - 4 <BR>\n" );
document.write( "l = 8\r<BR>\n" );
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document.write( "Does that work?<BR>\n" );
document.write( "28 = 12 + 16 check! </SPAN>\n" );
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