document.write( "Question 143597: please help me to answer this question, the directions are:
\n" ); document.write( "determine the intervals of increasing and decreasing.\r
\n" ); document.write( "\n" ); document.write( "f(x)=-2x^3-3x^2+12
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Algebra.Com's Answer #104511 by nabla(475)\"\" \"About 
You can put this solution on YOUR website!
f'(x)=-6x^2-6x
\n" ); document.write( "Find where it is=0\r
\n" ); document.write( "\n" ); document.write( "0=-6x^2-6x
\n" ); document.write( "0=6x(x+1)
\n" ); document.write( "implies x=0 or x=-1. These are our two critical values. Find out what happens outside and between these two values for the derivative f'.\r
\n" ); document.write( "\n" ); document.write( "f'(-2)=-6(-2)^2-6(-2)=-24+12=-12. It is decreasing from (\"-infinity\",-1).
\n" ); document.write( "f'(-1/2)=-6(-1/2)^2-6(-1/2)=-3/2+3=3/2. It is increasing from (-1,0).
\n" ); document.write( "f(1)=-6-6=-12. It is decreasing from (0,\"infinity\").\r
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\n" ); document.write( "\n" ); document.write( "Plot:
\n" ); document.write( "\"graph%28+300%2C+200%2C+-2%2C+2%2C+-20%2C+20%2C+-2x%5E3-3x%5E2%2B12+%29\"
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