document.write( "Question 143597: please help me to answer this question, the directions are:
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document.write( "determine the intervals of increasing and decreasing.\r
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document.write( "f(x)=-2x^3-3x^2+12 \n" );
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Algebra.Com's Answer #104511 by nabla(475)![]() ![]() ![]() You can put this solution on YOUR website! f'(x)=-6x^2-6x \n" ); document.write( "Find where it is=0\r \n" ); document.write( "\n" ); document.write( "0=-6x^2-6x \n" ); document.write( "0=6x(x+1) \n" ); document.write( "implies x=0 or x=-1. These are our two critical values. Find out what happens outside and between these two values for the derivative f'.\r \n" ); document.write( "\n" ); document.write( "f'(-2)=-6(-2)^2-6(-2)=-24+12=-12. It is decreasing from ( \n" ); document.write( "f'(-1/2)=-6(-1/2)^2-6(-1/2)=-3/2+3=3/2. It is increasing from (-1,0). \n" ); document.write( "f(1)=-6-6=-12. It is decreasing from (0, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plot: \n" ); document.write( " |