document.write( "Question 143607: 3 times the first of three consecutive numbers is 4 more than 2 times the second \n" ); document.write( "
Algebra.Com's Answer #104510 by nabla(475)\"\" \"About 
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Let's write symbols for the three numbers:
\n" ); document.write( "n1=x
\n" ); document.write( "n2=(x+1)
\n" ); document.write( "n3=(x+2)\r
\n" ); document.write( "\n" ); document.write( "So, we want 3n1=3x to be 4 more than 2n2=2(x+1)\r
\n" ); document.write( "\n" ); document.write( "Which is:
\n" ); document.write( "3x=2(x+1)+4
\n" ); document.write( "3x=2x+6
\n" ); document.write( "x=6.\r
\n" ); document.write( "\n" ); document.write( "This is the first number. The second number is x+1=6+1=7.
\n" ); document.write( "So the numbers are 6 and 7.\r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "3*6=18
\n" ); document.write( "2*7=14
\n" ); document.write( "18-14=4!\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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