document.write( "Question 143557: how do you evaluate the following expression:
\n" ); document.write( "log base square root 2 (2 sqaure root 2) \n" ); document.write( "

Algebra.Com's Answer #104472 by solver91311(24713) $\"\"$ $\"About$

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$\"log%28b%2Cx%29=y\"$ means $\"b%5Ey=x\"$ and $\"log%28b%2Cxy%29=log%28b%2Cx%29%2Blog%28b%2Cy%29\"$ , so\r
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\n" ); document.write( "\n" ); document.write( "if $\"y=log%28sqrt%282%29%2C2%29\"$ , then $\"%28sqrt%282%29%29%5Ey=2\"$ . If $\"%28sqrt%282%29%29%5Ey=2\"$ then $\"y=2\"$ \r
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\n" ); document.write( "\n" ); document.write( "if $\"z=log%28sqrt%282%29%2Csqrt%282%29%29\"$ , then $\"%28sqrt%282%29%29%5Ez=sqrt%282%29\"$ . If $\"%28sqrt%282%29%29%5Ez=sqrt%282%29\"$ , then $\"z=1\"$ (In fact, $\"log%28b%2Cb%29+=+1\"$ , always)\r
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