document.write( "Question 143550: the absolute value of 6x-8=10, then x= \n" ); document.write( "
Algebra.Com's Answer #104467 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"abs%286x-8%29=10\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29=a\", then \"x=-a\" or \"x=a\")\r
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\n" ); document.write( "\n" ); document.write( "\"6x-8=-10\" or \"6x-8=10\" Set the expression \"6x-8\" equal to the original value 10 and it's opposite -10\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the first equation \"6x-8=-10\"\r
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\n" ); document.write( "\n" ); document.write( "\"6x=-10%2B8\"Add 8 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"6x=-2\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-2%29%2F%286%29\" Divide both sides by 6 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=-1%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the second equation \"6x-8=10\"\r
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\n" ); document.write( "\n" ); document.write( "\"6x=10%2B8\"Add 8 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"6x=18\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2818%29%2F%286%29\" Divide both sides by 6 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=3\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So the solutions to \"abs%286x-8%29=10\" are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-1%2F3\" and \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=abs%286x-8%29\" and \"y=10\" (just set each side equal to y and graph), we get\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28500%2C500%2C-3%2C5%2C-10%2C10%2Cabs%286x-8%29%2C10%29\" Graph of \"y=abs%286x-8%29\" (red) and \"y=10\"(green)\r
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\n" ); document.write( "\n" ); document.write( "and we can see the two graphs intersect at \"x=-1%2F3\" and \"x=3\". So this verifies our answer.\r
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