document.write( "Question 143545: Hi i have a question that is really baffaling me.Can someone please help me?\r
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\n" ); document.write( "\n" ); document.write( "A jar of change has $90.15 in it.There are six less dimes than twice the nickels.There are three more quarters than 4 times the amount of nickels.How many nickels,dimes,and quarters are in the jar?(There are no pennies.)Thanks!!
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Algebra.Com's Answer #104464 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
90.15\r
\n" ); document.write( "\n" ); document.write( "Let n be the number of nickels
\n" ); document.write( "Dimes = 2n - 6 --> d = 2n - 6
\n" ); document.write( "Quarters = 4n + 3 --> q = 4n +3 \r
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\n" ); document.write( "\n" ); document.write( "9015 = 5n + 10d + 25q = n + 10*(2n - 6) + 25*(4n +3)
\n" ); document.write( "9015 = 5n + 20n - 60 + 100n + 75
\n" ); document.write( "9015 = 125n - 15
\n" ); document.write( "9000 = 125n
\n" ); document.write( "72 = n\r
\n" ); document.write( "\n" ); document.write( "d = 144 -6 = 138
\n" ); document.write( "q = 291\r
\n" ); document.write( "\n" ); document.write( "Does that check?
\n" ); document.write( "0.25*291 + 0.1*138 + 0.05* 72 = 90.15
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