document.write( "Question 143533: A reduced fat cookie contains 4 grams of fat per serving. In order for food to be termed \"reduced fat\", it must have at least 15% less fat than the regular item. What can you conclude about how much fat is in a serving of the regular cookie? \n" ); document.write( "
Algebra.Com's Answer #104459 by Fruglemiester1234(13)\"\" \"About 
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The main idea concerning this problem is percents. We have to use the information we already have, which is a number and a precent, to get us another number.
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\n" ); document.write( "First of all we have to realize that 15% is just 15 out of 100, or \"15%2F100.\"
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\n" ); document.write( "Knowing this we can right a porportion.
\n" ); document.write( "\"4%2Fx+=+15%2F100\"
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\n" ); document.write( "Note: the 4 goes on the top of the porportion because 4 grams is the reduced amount of fat and is at least 15% of the normal amount of fat(x) that we are looking for.
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\n" ); document.write( "Now to solve the porportion we use cross multiplication. We get:
\n" ); document.write( "\"4%2A100+=+15x\"
\n" ); document.write( "\"400+=+15x\"
\n" ); document.write( "Then we divide both sides by 15 to get x by itself.
\n" ); document.write( "\"400%2F15+=+15x%2F15\"
\n" ); document.write( "\"26.67+=+x\" or 26_2/3 (80/3) to be exact
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\n" ); document.write( "\n" ); document.write( "x = 26.67 means that in order for the \"reduced fat\" cookie to be legally reduced fat the normal cookie has to have at least 26.67 grams of fat.
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\n" ); document.write( "This could also be written mathmatically like:
\n" ); document.write( "\"x+%3E=+26.67\" or \"x+%3E=+80%2F3\"
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