document.write( "Question 143528: I just want to make sure I have the right answer, if I don't could you please explain the steps to me.\r
\n" ); document.write( "\n" ); document.write( "Problem---Find the area of a rectangle whose width is √2 and whose length is √40. Show your work. Write “Sqrt” to show √.\r
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\n" ); document.write( "Sqrt2 X Sqrt40 = Sqrt80
\n" ); document.write( "Sqrt80 = sqrt64 X 16
\n" ); document.write( "Sqrt 64 X 16 = 8 sqrt16\r
\n" ); document.write( "\n" ); document.write( "Area = 8 sqrt16
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Algebra.Com's Answer #104455 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"A=L%2AW\" Start with the area formula\r
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\n" ); document.write( "\n" ); document.write( "\"A=sqrt%282%29%2Asqrt%2840%29\" Plug in \"L=sqrt%282%29\" and \"sqrt%2840%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=sqrt%282%2A40%29\" Combine the square roots\r
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\n" ); document.write( "\n" ); document.write( "\"A=sqrt%2880%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"A=sqrt%2816%2A5%29\" Factor 80 into 16*5
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\n" ); document.write( "\n" ); document.write( "\"A=sqrt%2816%29%2Asqrt%285%29\" Break up the square root
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\n" ); document.write( "\n" ); document.write( "\"A=4%2Asqrt%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "So the area is \"A=4%2Asqrt%285%29\"
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