document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143521>Question 143521</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much Flam would be needed to produce 10 pounds of Flim? When 52 pounds of Flam produce 13 pounds of Flim? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104447 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 13x=52<BR>\n" );
document.write( "x=52/13\r<BR>\n" );
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document.write( "This means 1 lb of flim takes 52/13 flam.<BR>\n" );
document.write( "Thus, 10*52/13=520/13=40 lb of flam would be required to produce 10 lb of flim. </SPAN>\n" );
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