document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143504>Question 143504</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Would someone be able to help me with this, I appreciate it.\r<BR>\n" );
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document.write( "Solve the following system by graphing.<BR>\n" );
document.write( "x + y = 6<BR>\n" );
document.write( "x - y = 3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104446 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> plot y=6-x and y=x-3  and see the place where they intersect.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+6-x%2C+x-3+%29 ALIGN=MIDDLE  ALT=\"graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+6-x%2C+x-3+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Looks like y=3/2 and x=9/2.\r<BR>\n" );
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document.write( "Check via substitution:<BR>\n" );
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document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=linear_substitution.solver>SOLVE linear system by SUBSTITUTION</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT>Solve:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+6%2C%0D%0A++++1%5Cx+%2B+-1%5Cy+=+3+%29%0D%0A++ ALIGN=MIDDLE  ALT=\"+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+6%2C%0D%0A++++1%5Cx+%2B+-1%5Cy+=+3+%29%0D%0A++\"   DISABLED_style= \"max-width:90%; height:auto;\" >We'll use substitution. After moving 1*y to the right, we get:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2Ax+=+6+-+1%2Ay ALIGN=MIDDLE  ALT=\"1%2Ax+=+6+-+1%2Ay\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+6%2F1+-+1%2Ay%2F1 ALIGN=MIDDLE  ALT=\"x+=+6%2F1+-+1%2Ay%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Substitute that<BR>\n" );
document.write( "  into another equation:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2A%286%2F1+-+1%2Ay%2F1%29+%2B+-1%5Cy+=+3 ALIGN=MIDDLE  ALT=\"1%2A%286%2F1+-+1%2Ay%2F1%29+%2B+-1%5Cy+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > and simplify: So, we know that y=1.5. Since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+6%2F1+-+1%2Ay%2F1 ALIGN=MIDDLE  ALT=\"x+=+6%2F1+-+1%2Ay%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >, x=4.5.<BR>\n" );
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document.write( "  Answer: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28+x=4.5%2C+y=1.5+%29 ALIGN=MIDDLE  ALT=\"system%28+x=4.5%2C+y=1.5+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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