document.write( "Question 143460: find vertex and intercept coordinates of the following
\n" ); document.write( "a=b^2-6b-16 \n" ); document.write( "
Algebra.Com's Answer #104432 by nabla(475)\"\" \"About 
You can put this solution on YOUR website!
Let's rewrite it because the symbols are poorly chosen.
\n" ); document.write( "y=x^2-6x-16\r
\n" ); document.write( "\n" ); document.write( "The vertex of ax^2+bx+c=0 is x=-b/2a.
\n" ); document.write( "For this problem we have x=6/2=3, which gives a y-value of 9-18-16=-25. Vertex is (3,-25).\r
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\n" ); document.write( "\n" ); document.write( "Intercepts:
\n" ); document.write( "x-intercepts: 0=x^2-6x-16
\n" ); document.write( "Factor:
\n" ); document.write( "0=(x-8)(x+2)
\n" ); document.write( "Which implies x=8 or x=-2. In point form, (8,0), (-2,0)\r
\n" ); document.write( "\n" ); document.write( "y-intercepts:
\n" ); document.write( "set x=0
\n" ); document.write( "y=-16. In point form, (0,-16).\r
\n" ); document.write( "\n" ); document.write( "Here is the graph:
\n" ); document.write( "\"graph%28+300%2C+200%2C+-5%2C+10%2C+-25%2C+25%2C+x%5E2-6x-16+%29\"\r
\n" ); document.write( "\n" ); document.write( "E-mail me at enabla@gmail.com if you have further difficulty. \n" ); document.write( "
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