document.write( "Question 143495: a man stands atop a building. he measures the angle of elevation to the building across the street to be 20 degrees and the angle of depression(to the base of the building) to be 35 degrees. if two buildings are 50 feet apart how tall is the taller building. please show all work and find the solution \n" ); document.write( "

Algebra.Com's Answer #104425 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
You have two right triangles.
\n" ); document.write( "Both have an adjacent leg of 50 ft. \r
\n" ); document.write( "\n" ); document.write( "Looking up at 20degrees. The opposite leg of the 'upper triangle' can be found by
\n" ); document.write( " $\"tan%2820%29+=+opposite%2Fadjacent\"$
\n" ); document.write( " $\"0.364+=+opposite%2F50\"$
\n" ); document.write( " $\"18.20+=+opposite\"$ \r
\n" ); document.write( "\n" ); document.write( "Looking down at 35 degrees. The opposite leg of the lower triangle' can be found by
\n" ); document.write( " $\"tan%2835%29+=+opposite%2Fadjacent\"$
\n" ); document.write( " $\"0.7+=+opposite%2F50\"$
\n" ); document.write( " $\"35.01+=+opposite\"$ \r
\n" ); document.write( "\n" ); document.write( "So the next building is $\"18.20+%2B+35.01+ft\"$ = 53.21ft high
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