document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143493>Question 143493</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if sec0=3 and tan0=2sqr root 2 what are the values of\r<BR>\n" );
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document.write( "cot0\r<BR>\n" );
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document.write( "sin0 \r<BR>\n" );
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document.write( "cos^2 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104421 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By the use of 0 you mean theta,&#952;, correct?\r<BR>\n" );
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document.write( "(1)  sec(&#952;)=3=1/cos(&#952;)<BR>\n" );
document.write( "(2)  tan(&#952;)=2sqrt(2)=1/cot(&#952;)=sin(&#952;)/cos(&#952;)\r<BR>\n" );
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document.write( "a. cot(&#952;)=?<BR>\n" );
document.write( " From (2) we notice that cot(&#952;)=1/(2sqrt(2))=sqrt(2)/4<BR>\n" );
document.write( "b. sin(&#952;)=?<BR>\n" );
document.write( " From (1) and (2) we see that sin(&#952;)=cos(&#952;)tan(&#952;)=(1/3)*2sqrt(2)=(2/3)sqrt(2)<BR>\n" );
document.write( "c. cos^2(&#952;)=?<BR>\n" );
document.write( " From (1) we can see that cos(&#952;)=1/3, thus cos^2(&#952;)=1/9\r<BR>\n" );
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document.write( " </SPAN>\n" );
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