document.write( "Question 143487: A rectangular field is 260 feet in perimeter.the length is 10 feet more than twice the width.what is the length? \n" ); document.write( "

Algebra.Com's Answer #104418 by vleith(2983) $\"\"$ $\"About$

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Let the width = w.
\n" ); document.write( "The length is given as \"10 feet more than twice the width\". So $\"l+=+10%2B2w\"$ \r
\n" ); document.write( "\n" ); document.write( "The perimeter is givenb as 260 feet. You know the perimeter of a rectangle is
\n" ); document.write( " $\"P+=+2w+%2B+2l\"$
\n" ); document.write( " $\"260+=+2w+%2B+2%2810%2B2w%29+\"$
\n" ); document.write( " $\"260+=+2w+%2B+20+%2B+4w+\"$
\n" ); document.write( " $\"260+-+20+=+2w+%2B+4w+\"$
\n" ); document.write( " $\"240+=+6w+\"$
\n" ); document.write( " $\"40+=+w+\"$ \r
\n" ); document.write( "\n" ); document.write( "Check your answer.
\n" ); document.write( "If w = 40 , then length = 10+80 = 90.\r
\n" ); document.write( "\n" ); document.write( "Is 2*40 + 2+90 = 260?? \n" ); document.write( "

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