document.write( "Question 143459: find the vertex and intercept coordinates of the following.\r
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document.write( "y=x^2-5x-4 \n" );
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Algebra.Com's Answer #104410 by nabla(475)![]() ![]() ![]() You can put this solution on YOUR website! Set y=0 :\r \n" ); document.write( "\n" ); document.write( "x^2-5x-4=0\r \n" ); document.write( "\n" ); document.write( "Use the quadratic formula to find where y is zero (the x-intercepts): \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To find the y intercept we set x=0;\r \n" ); document.write( "\n" ); document.write( "0^2-5(0)-4=y \n" ); document.write( "It follows that y=-4. Thus, (0,-4) is the y-intercept.\r \n" ); document.write( "\n" ); document.write( "The vertex is x=-b/(2a) when the equation is in form ax^2+bx+c=0. Thus, 5/2=x is the vertex. Now, find the corresponding y coordinate for x=5/2. \r \n" ); document.write( "\n" ); document.write( "(5/2)^2-5(5/2)-4=25/4-50/4-16/4=-41/4 \n" ); document.write( "Thus, the vertex is at (5/2,-41/4). The graph is above. \n" ); document.write( " |