document.write( "Question 2444: One dimension of a square is increased by 10 meters and the other dimension is increased by 5 meters. The area of the new rectangle is three times that of the original square. How long was one side of the square? \n" ); document.write( "
Algebra.Com's Answer #1044 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
Let side of square be x\r
\n" ); document.write( "\n" ); document.write( "so, area of square = x^2\r
\n" ); document.write( "\n" ); document.write( "Rectangle will have length = x+10 and width = x+5\r
\n" ); document.write( "\n" ); document.write( "so, area of rectangle = (x+10)(x+5)\r
\n" ); document.write( "\n" ); document.write( "We are told that rectangle area = 3(square area), so...\r
\n" ); document.write( "\n" ); document.write( "(x+10)(x+5) = 3x^2
\n" ); document.write( "x^2 + 15x + 50 = 3x^2
\n" ); document.write( "2x^2 - 15x - 50 = 0
\n" ); document.write( "(2x + 5)(x - 10) = 0\r
\n" ); document.write( "\n" ); document.write( "so 2x+5=0 OR x-10=0\r
\n" ); document.write( "\n" ); document.write( "x=-5/2 or x=10\r
\n" ); document.write( "\n" ); document.write( "Physically, x=10m.\r
\n" ); document.write( "\n" ); document.write( "jon
\n" ); document.write( "
\n" ); document.write( "
\n" );