document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143414>Question 143414</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395352495/algebrahomeworkh>algebra: structure and method: book1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Pipe A can fill a tank in 2 hours and Pipe B can fill ii in half the it takes Pipe C to empty it. When all 3 are opened, it takes 1.5 hours to fill the pool. How much time is required for Pipe C to empty the tank? PLEASE HELP! The answer is 6 hours, but I don't know how to get there. HELP MUCH APPRECIATED!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104378 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "YOU ARE CORRECT!!! THE ANSWER IS SIX HOURS.<BR>\n" );
document.write( "Let t=time required for Pipe C to empty the tank<BR>\n" );
document.write( "Pipe C empties the tank at the rate of 1/t tank per hour<BR>\n" );
document.write( "Pipe A fills at the rate of 1/2 tank per hour<BR>\n" );
document.write( "Pipe B fills tha tank in t/2 hours, so<BR>\n" );
document.write( "Pipe B fills at the rate of 2/t tank per hour\r<BR>\n" );
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document.write( "When all three pipes are open they fill at the rate of 1/1.5 tank per hour.  So our equation to solve is:\r<BR>\n" );
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document.write( "1/2+2/t-1/t=1/1.5  simplify<BR>\n" );
document.write( "1/2+1/t=1/1.5  multiply each term by 6t\r<BR>\n" );
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document.write( "3t+6=4t  subtract 3t from each side\r<BR>\n" );
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document.write( "3t-3t+6=4t-3t  collect like terms\r<BR>\n" );
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document.write( "6=t or<BR>\n" );
document.write( "t=6 hours------------------time required for Pipe C to empty the tank\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "1/2+1/6=1/1.5<BR>\n" );
document.write( "3/6+1/6=1/1.5<BR>\n" );
document.write( "4/6=1/1.5<BR>\n" );
document.write( "1/1.5=1/1.5\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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