document.write( "Question 143381This question is from textbook algebra: structure and method: book1
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document.write( ": Pipe A can fill a tank in 2 hours and Pipe B can fill ii in half the it takes Pipe C to empty it. When all 3 are opened, it takes 1.5 hours to fill the pool. How much time is required for Pipe C to empty the tank? PLEASE HELP! The answer is 6 hours, but I don't know how to get there. HELP MUCH APPRECIATED!! \n" );
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Algebra.Com's Answer #104374 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Pipe A can fill a tank in 2 hours and Pipe B can fill it in half the time it takes \n" ); document.write( " Pipe C to empty it. When all 3 are opened, it takes 1.5 hours to fill the pool. \n" ); document.write( " How much time is required for Pipe C to empty the tank? \n" ); document.write( ": \n" ); document.write( "Let t = time required for Pipe C to empty the tank: \n" ); document.write( ": \n" ); document.write( "It says, \"Pipe B can fill it in half the time it takes Pipe C to empty it.\" \n" ); document.write( "therefore: \n" ); document.write( "Let .5t = time for Pipe B to fill the tank \n" ); document.write( ": \n" ); document.write( "Let the full pool = 1 \n" ); document.write( ": \n" ); document.write( "Filling is positive, emptying is negative: \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply equation 2t, to get rid of the denominators: \n" ); document.write( "1.5t + 1.5(4) - 1.5(2) = 2t(1) \n" ); document.write( ": \n" ); document.write( "1.5t + 6 - 3 = 2t \n" ); document.write( ": \n" ); document.write( "1.5t - 2t = +3 - 6 \n" ); document.write( ": \n" ); document.write( "-.5t = -3 \n" ); document.write( "t = \n" ); document.write( "t = +6 hrs for the pipe to empty a full pool \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution using original equation: \n" ); document.write( " \n" ); document.write( ".75 + .5 - .25 = 1; confirms our solution \n" ); document.write( " |