document.write( "Question 143415This question is from textbook algebra: structure and method: book1
\n" ); document.write( ": Carla can ride her bike 2 mph faster than Karen. It takes Carla 48 minutes less to travel 50 miles than it does Karen. What is Carla's rate (mph)? HELP MUCH APPRECIATED!!!! \n" ); document.write( "
Algebra.Com's Answer #104371 by solver91311(24713)\"\" \"About 
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Karen travels 50 miles in t hours at r miles per hour. Carla travels 50 miles in \"t-48%2F60=t-4%2F5\" hours at \"r%2B2\" miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "Since \"d=rt\", Karen's trip is described by \"50=rt\" and Carla's trip is described by \"50=%28r%2B2%29%28t-4%2F5%29\"\r
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\n" ); document.write( "\n" ); document.write( "From the description of Karen's trip we can say: \"t=50%2Fr\", so Carla's trip can be described as:\r
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\n" ); document.write( "\n" ); document.write( "\"50=%28r%2B2%29%28%2850%2Fr%29-4%2F5%29\"
\n" ); document.write( "\"50=%28r%2B2%29%28%28250-4r%29%2F5r%29\"
\n" ); document.write( "\"250r=%28r%2B2%29%28250-4r%29\"\r
\n" ); document.write( "\n" ); document.write( "Apply FOIL:
\n" ); document.write( "\"250r=250r-4r%5E2%2B500-8r\"\r
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\n" ); document.write( "\n" ); document.write( "Collect terms, put in standard form:
\n" ); document.write( "\"4r%5E2%2B8r-500=0\"\r
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\n" ); document.write( "\n" ); document.write( "Solve the quadratic:
\n" ); document.write( "\"r%5E2%2B2r-125\"\r
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\n" ); document.write( "\n" ); document.write( "Either complete the square or use the quadratic formula. You get:\r
\n" ); document.write( "\n" ); document.write( "\"r=-1+%2B-+3sqrt%2814%29\". Exclude the negative root, so Karen's rate was \"-1+%2B+3sqrt%2814%29\" mph, and Carla's was 2 mph faster or \"1%2B3sqrt%2814%29\" mph
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