document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143375>Question 143375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to know what are the steps to find out this question:\r<BR>\n" );
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document.write( "x= 2y-1 <BR>\n" );
document.write( "3x-3y=9\r<BR>\n" );
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document.write( "My textbook is the Glencoe Alegebra 1 for Florida.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104360 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=2y-1 NOW REPLACE X WITH (2Y-1) & SOLVE FOR Y  IN THE SECOND EQUATION.<BR>\n" );
document.write( "3x-3y=9<BR>\n" );
document.write( "3(2Y-1)-3Y=9<BR>\n" );
document.write( "6Y-3-3Y=9<BR>\n" );
document.write( "3Y=9+3<BR>\n" );
document.write( "3Y=12<BR>\n" );
document.write( "Y=12/3<BR>\n" );
document.write( "Y=4 ANSWER.<BR>\n" );
document.write( "X=2*4-1<BR>\n" );
document.write( "X=8-1<BR>\n" );
document.write( "X=7 ANSWER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "3*7-3*4=9<BR>\n" );
document.write( "21-12=9<BR>\n" );
document.write( "9=9<BR>\n" );
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