document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143396>Question 143396</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321361466/algebrahomeworkh>Mathematical Ideas</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I am stuck on this linear equation story problem. I was hoping someone could please help me with the formula that I need.\r<BR>\n" );
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document.write( "The Candy Shop wants to create 50 pounds of a holiday mix that will sell for $3.91 per pound.  How many pounds of a candy selling for $2.59 per pound should be combined with candy selling for $6.99 per pound to create the desired mix?  \r<BR>\n" );
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document.write( "Set up a system of equations to describe this situation.  Solve the system of equations to find the solution.\r<BR>\n" );
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document.write( "This isn't from a book, it is from a problem in one of my online classes. Thanks so much ~Lyn </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104354 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> he Candy Shop wants to create 50 pounds of a holiday mix that will sell for $3.91 per pound. How many pounds of a candy selling for $2.59 per pound should be combined with candy selling for $6.99 per pound to create the desired mix?<BR>\n" );
document.write( "Set up a system of equations to describe this situation. Solve the system of equations to find the solution. <BR>\n" );
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document.write( "Let x = amt of 2.59 candy required (to make a 50 lb mixture)<BR>\n" );
document.write( "Let y = amt of 6.99 candy required<BR>\n" );
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document.write( "Total lb amt equation:<BR>\n" );
document.write( "x + y = 50<BR>\n" );
document.write( "y = (50-x); use this for substitution<BR>\n" );
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document.write( "The $ value equation:<BR>\n" );
document.write( "2.59x + 6.99y = 3.91(50)<BR>\n" );
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document.write( "2.59x + 6.99y = 195.50<BR>\n" );
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document.write( "Substitute (50-x) for y in the above equation, find x:<BR>\n" );
document.write( "2.59x + 6.99(50-x) = 195.50<BR>\n" );
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document.write( "2.59x + 349.50 - 6.99x = 195.50<BR>\n" );
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document.write( "2.59x - 6.99x = 195.50 - 349.50<BR>\n" );
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document.write( "-4.40x = -154<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-154%29%2F%28-4.4%29 ALIGN=MIDDLE  ALT=\"%28-154%29%2F%28-4.4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = +35 lb of $2.59 candy<BR>\n" );
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document.write( "Then y = 50 - 35 = 15 lb of $6.99 candy<BR>\n" );
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document.write( "Check solutions in the $$ equation:<BR>\n" );
document.write( "2.59(35) + 6.99(15) = 195.50<BR>\n" );
document.write( "90.65 + 104.85 = 195.50 </SPAN>\n" );
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