document.write( "Question 143397This question is from textbook amscos mathematics b
\n" ); document.write( ": givin am+cn
\n" ); document.write( " Mb=Nd\r
\n" ); document.write( "\n" ); document.write( "Prove ab+cd
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Algebra.Com's Answer #104350 by solver91311(24713)\"\" \"About 
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The way you have written this problem makes no sense. Given am+cn? am+cn equals what? Also, was there a figure included?\r
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\n" ); document.write( "\n" ); document.write( "Now, if you just made a mistake typing and meant:\r
\n" ); document.write( "\n" ); document.write( "Given \"am=cn\" and \"mb=nd\" then prove \"ab=cd\", then there is no solution. That is because with the given relations, \"ab%3C%3Ecd\" in general. It can be proven that \"ad=bc\" however.
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