document.write( "Question 143392: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 90 miles per hour. Train A passes a station at 5:15 A.M. If train B passes the same station at 5:45 A.M., at what time will train B catch up to train A?
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Algebra.Com's Answer #104347 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 90 miles per hour. Train A passes a station at 5:15 A.M. If train B passes the same station at 5:45 A.M., at what time will train B catch up to train A? \n" ); document.write( "__:___AM/PM \n" ); document.write( ": \n" ); document.write( "From the information given we can say: \n" ); document.write( ": \n" ); document.write( "Train A has traveled .5 * 80 = 40 mi, from the station, when Train B passes the station.: \n" ); document.write( ": \n" ); document.write( "Let t = time (in hrs) for B to catch up with A, from the station \n" ); document.write( ": \n" ); document.write( "When B catches A they will have traveled the same distance from the station \n" ); document.write( "Write a dist equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "90t = 80t + 40 \n" ); document.write( ": \n" ); document.write( "90t - 80t = 40 \n" ); document.write( "t = \n" ); document.write( "t = 4 hrs \n" ); document.write( ": \n" ); document.write( "B catches A at 9:45 AM \n" ); document.write( ": \n" ); document.write( "Check solution; confirm the dist from the station for each train is the same \n" ); document.write( "90*4 = 360 mi \n" ); document.write( "80*4 + 40 = 360 mi \n" ); document.write( " |