document.write( "Question 143213: 3^(2x-1)=4^(x=2) \n" ); document.write( "
Algebra.Com's Answer #104342 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Assume you mean:
\n" ); document.write( ":
\n" ); document.write( "3^(2x-1) = 4^(x+2)
\n" ); document.write( ":
\n" ); document.write( "log(3^(2x-1)) = log(4^(x+2))
\n" ); document.write( ":
\n" ); document.write( "Use the log equiv of exponents
\n" ); document.write( "(2x-1)*log(3) = (x+2)*log(4)
\n" ); document.write( ":
\n" ); document.write( "Find the logs of 3 and 4 and you have:
\n" ); document.write( ".47712(2x-1) = .60206(x+2)
\n" ); document.write( ":
\n" ); document.write( "Multiply what's inside the brackets:
\n" ); document.write( " .95424x - .47712 = .60206x + 1.20412
\n" ); document.write( ":
\n" ); document.write( " .95424x - .60206x = .47712 + 1.20412
\n" ); document.write( ":
\n" ); document.write( ".35218x = 1.68124
\n" ); document.write( "x = \"1.68124%2F.35218\"
\n" ); document.write( "x = 4.7738
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution using a calc:
\n" ); document.write( "enter 3^(2(4.7738)-1) = 11974
\n" ); document.write( "and
\n" ); document.write( "enter 4^6.7738 = 11974; confirms our solution \n" ); document.write( "
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