document.write( "Question 143316: A fertilizer is to be diluted with water so that the fertilizer is just 1% of the solution. How much water should be mixed with 5cm^3 of fertilizer? \n" ); document.write( "

Algebra.Com's Answer #104319 by ptaylor(2198) $\"\"$ $\"About$

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\n" ); document.write( "Let x=amount of water needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure fertilizer before the mixture takes place (5 cm^3)(Note: 5cm^3 *100% or 5cm^3*1 or 5cm^3) has to equal the amount of pure fertilizer in the final mixture 0.01(5+x) so our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "5=0.01(5+x) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "5=0.05+0.01x subtract 0.05 from each side\r
\n" ); document.write( "\n" ); document.write( "5-0.05=0.05-0.05+0.01x collect like terms\r
\n" ); document.write( "\n" ); document.write( "4.95=0.01x divide each side by 0.01\r
\n" ); document.write( "\n" ); document.write( "x=495 cm^3------------------------amount of water needed\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "5cm^3=0.01(5cm^3+495cm^3)
\n" ); document.write( "5cm^3=0.01(500cm^3)
\n" ); document.write( "5cm^3=5cm^3\r
\n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor \n" ); document.write( "

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