document.write( "Question 143346: Working together, Jenny and Natalie can mop a warehouse in 5.14 hours. Had she done it alone it would have taken Natalie 12 hours. How long would it take Jenny to do it alone? \n" ); document.write( "
Algebra.Com's Answer #104318 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Working together, Jenny and Natalie can mop a warehouse in 5.14 hours. Had she done it alone it would have taken Natalie 12 hours. How long would it take Jenny to do it alone? \n" ); document.write( ": \n" ); document.write( "Let t = time required for J to do the job alone \n" ); document.write( "; \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply equation by 12t to get rid of the denominators: \n" ); document.write( ": \n" ); document.write( "5.14t + 12(5.14) = 12t(1) \n" ); document.write( ": \n" ); document.write( "5.14t + 61.68 = 12t \n" ); document.write( ": \n" ); document.write( "61.68 = 12t - 5.14t \n" ); document.write( ": \n" ); document.write( "61.68 = 6.86t \n" ); document.write( "t = \n" ); document.write( "t = 8.99 ~ 9 hrs J's time alone \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution using original equation \n" ); document.write( "5.14/12 + 5.14/9 = \n" ); document.write( ".4283 + .5711 = .999 ~ 1 \n" ); document.write( " \n" ); document.write( " |