document.write( "Question 143340: Brand X sells 21 oz bags of mixed nuts that contain 29% peanuts. To make their product they combine Brand A mixed nuts which contain 35% peanuts and Brand B mixed nuts which contain 25% peanuts. How much of each do they need to use? \n" ); document.write( "

Algebra.Com's Answer #104316 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x=Amount of Brand A
\n" ); document.write( "Then 21-x=Amount of Brand B\r
\n" ); document.write( "\n" ); document.write( "Amount of peanuts in Brand A and B before the mixture takes place has to equal the amount of peanuts in the final mixture, so our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.35x+0.25(21-x)=21*0.29 get rid of parens (distributive law)
\n" ); document.write( "0.35x+5.25-0.25x=6.09 subtract 5.25 from each side\r
\n" ); document.write( "\n" ); document.write( "0.35x+5.25-5.25-0.25x=6.09-5.25 collect like terms\r
\n" ); document.write( "\n" ); document.write( "0.10x=0.84 divide each side by 0.10
\n" ); document.write( "x=8.4 oz---------------------------------Amount of Brand A needed
\n" ); document.write( "21-x=21-8.4=12.6-----------------------------Amount of Brand B needed\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "8.4*0.35+12.6*0.25=21*0.29
\n" ); document.write( "2.94+3.15=6.09
\n" ); document.write( "6.09=6.09\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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