document.write( "Question 143280: A rectangular painting has dimensions X and X+10. the painting is in a frame 2 in. wide. The total area of the picture and the frame is 900 in^2. What are the dimensions of the painting? \n" ); document.write( "

Algebra.Com's Answer #104288 by checkley77(12844) $\"\"$ $\"About$

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(X+2*2)(X+10+2*2)=900
\n" ); document.write( "(X+4)(X+10+4)=900
\n" ); document.write( "(X+4)(X+14)=900
\n" ); document.write( "X^2+18X+56-900=0
\n" ); document.write( "X^2+18X-844=0
\n" ); document.write( "USING THE QUADRATIC EQUATION $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$ WE GET:
\n" ); document.write( "X=(-18+-SQRT[18^2-4*1*-844])/2*1
\n" ); document.write( "X=(-18+-SQRT[324+3376])/2
\n" ); document.write( "X=(-18+-SQRT3700)/2
\n" ); document.write( "X=(-18+-60.83)/2
\n" ); document.write( "X=(-18+60.38)/2
\n" ); document.write( "X=42.82/2
\n" ); document.write( "X=21.41 IS THE SHORT SIDE OF THE PICTURE.
\n" ); document.write( "21.41+10=31.41 IS THE LONG SIDE OF THE PICTURE.
\n" ); document.write( "PROOF:
\n" ); document.write( "(21.41+4)(31.41+4)=900
\n" ); document.write( "25.41*35.41=900
\n" ); document.write( "899.77~900
\n" ); document.write( " \n" ); document.write( "

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