document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143290>Question 143290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangular parcel of land is 720 square meters. The length of the land is 4 meters less than twice the width.<BR>\n" );
document.write( "A. Write an equation that can be used to find the dimensions of the land.<BR>\n" );
document.write( "B. Solve the equation written in part A to find the dimensions of the land.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104282 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AREA=L*W<BR>\n" );
document.write( "A) 720=(2W-4)W<BR>\n" );
document.write( "B) 720=2W^2-4W<BR>\n" );
document.write( "2W^2-4W-720=0<BR>\n" );
document.write( "2(W^2-2W-360)=0<BR>\n" );
document.write( "2(W-20)(W+18)=0<BR>\n" );
document.write( "W-20=0<BR>\n" );
document.write( "W=20 FOR THE WIDTH.<BR>\n" );
document.write( "L=2*20-4<BR>\n" );
document.write( "L=40-4<BR>\n" );
document.write( "L=36 FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "20*36=720<BR>\n" );
document.write( "720=720\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );