document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143297>Question 143297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help in solving the following.  Thank you.\r<BR>\n" );
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document.write( "A rectangular garden has dimensions of 23ft by 11ft.  A gravel path of equal width is to be built around the garden.  How wide can the path be if there is enough gravel for 240 square feet.  I was trying to solve this by using the formula (23-2x)(11-2x) = 240 but I cant find the solution to work.  Any help would be appreciated to point me in the right direction.  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104277 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 23*11=253^ft is the area of the garden<BR>\n" );
document.write( "(23+2x)(11+2x)=253+240<BR>\n" );
document.write( "253+22x+46x+4x^2=493<BR>\n" );
document.write( "4x^2+68x+253-493=0<BR>\n" );
document.write( "4x^2+68x-240=0<BR>\n" );
document.write( "4(x^2+17x-60)=0<BR>\n" );
document.write( "4(x-3)(x+20)=0<BR>\n" );
document.write( "x-3=0<BR>\n" );
document.write( "x=3 ft. for the width of the path.<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( "(23+2*3)(11+2*3)=493<BR>\n" );
document.write( "(23+6)(11+6)=493<BR>\n" );
document.write( "29*17=493<BR>\n" );
document.write( "493=493 </SPAN>\n" );
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