document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143251>Question 143251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motor boat traveled 12 miles with the current, turned around, and returned 12 miles against the current to its starting point. The trip with the current took 2 hours and the trip against the current took 3 hours. Find the speed of the boat and the speed of the current.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104248 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> DISTANCE=RATE*TIME<BR>\n" );
document.write( "T=D/R<BR>\n" );
document.write( "2=12/R<BR>\n" );
document.write( "2R=12<BR>\n" );
document.write( "R=6 MPH. FOR THE 2 HOUR TRIP.<BR>\n" );
document.write( "3=12/R<BR>\n" );
document.write( "3R=12<BR>\n" );
document.write( "R=12/3<BR>\n" );
document.write( "R=4 MPH. FOR THE 3 HOUR TRIP.<BR>\n" );
document.write( "(6-4)/2=2/2=1 MPH IS THE CURRENT.<BR>\n" );
document.write( "SPEED OF THE BOAT IS 6-1=5 MPH. FOR THE BOAT<BR>\n" );
document.write( "OR 4+1=5 MPH. FOR THE BOAT </SPAN>\n" );
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