document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143241>Question 143241</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of b if a = 10 and c = 16<BR>\n" );
document.write( "I have figured it out as far as I can, but I am now stuck and I don't know what to do, so if you could put down every single step I would appreciate it!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104234 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We basically have a triangle like this set up:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28500%2C500%2C-0.5%2C2%2C-0.5%2C3.2%2C%0D%0A%0D%0Aline%280%2C0%2C0%2C3%29%2C%0D%0Aline%280%2C3%2C2%2C0%29%2C%0D%0Aline%282%2C0%2C0%2C0%29%2C%0D%0Alocate%28-0.2%2C1.5%2C10%29%2C%0D%0Alocate%281%2C-0.2%2Cx%29%2C%0D%0Alocate%281%2C2%2C16%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Since we can see that the triangle has legs of 10 and x with a hypotenuse of 16, we can use Pythagoreans theorem to find the unknown side.\r<BR>\n" );
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document.write( "Pythagoreans theorem:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2Bb%5E2=c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2Bb%5E2=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where a and b are the legs of the triangle and c is the hypotenuse\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5E2%2Bx%5E2=16%5E2 ALIGN=MIDDLE  ALT=\"10%5E2%2Bx%5E2=16%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Plug in a=10, b=x, and c=16. Now lets solve for x\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+0+0+%2B++x++%5E+2+=+2+5+6 ALIGN=MIDDLE  ALT=\"1+0+0+%2B++x++%5E+2+=+2+5+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > Square each individual term\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x++%5E+2+=+2+5+6+-+1+0+0 ALIGN=MIDDLE  ALT=\"+x++%5E+2+=+2+5+6+-+1+0+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 100 from both sides\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x++%5E+2+=+1+5+6 ALIGN=MIDDLE  ALT=\"+x++%5E+2+=+1+5+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like terms\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+q+r+t+%28++x++%5E+2+%29+=+s+q+r+t+%28+1+5+6+%29 ALIGN=MIDDLE  ALT=\"s+q+r+t+%28++x++%5E+2+%29+=+s+q+r+t+%28+1+5+6+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=2%2Asqrt%2839%29 ALIGN=MIDDLE  ALT=\"x=2%2Asqrt%2839%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify the square root\r<BR>\n" );
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document.write( "So our answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=2%2Asqrt%2839%29 ALIGN=MIDDLE  ALT=\"x=2%2Asqrt%2839%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > which is approximately <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=12.49 ALIGN=MIDDLE  ALT=\"x=12.49\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the value of b is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=2%2Asqrt%2839%29 ALIGN=MIDDLE  ALT=\"b=2%2Asqrt%2839%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > which is approximately <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=12.49 ALIGN=MIDDLE  ALT=\"b=12.49\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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