document.write( "Question 143204: 3^x=40 \r
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document.write( "e^0.04t=1500\r
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document.write( "please help me solve these... if possible...i need good step by step process\r
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Algebra.Com's Answer #104225 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! Use logs\r \n" ); document.write( "\n" ); document.write( "Given: \n" ); document.write( "Take the log of both sides \n" ); document.write( " \n" ); document.write( "When using logs, if the term inside parens is raised to a power, then your can 'bring the power down' as a multiplier. \n" ); document.write( " \n" ); document.write( "Now get out your handy calculator and find log(3) and log(40) \n" ); document.write( " \n" ); document.write( "Now solve for x as a one step algebra simplification \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Finally, check your answer using a calculator. Does 3^3.3576 = 40? Close enough!\r \n" ); document.write( "\n" ); document.write( "For the second problem, use logs again. Except this time, use natural log (ln) \n" ); document.write( "Given: \n" ); document.write( "Take the ln of both sides \n" ); document.write( " \n" ); document.write( "The ln of a power of e, it just the power. \n" ); document.write( " \n" ); document.write( "Whip out your calculator and find ln(1500) (somebody help that man!) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check your answer using the calculator. Does it check out? You bet it does,\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |