document.write( "Question 143204: 3^x=40 \r
\n" ); document.write( "\n" ); document.write( "e^0.04t=1500\r
\n" ); document.write( "\n" ); document.write( "please help me solve these... if possible...i need good step by step process\r
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Algebra.Com's Answer #104225 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Use logs\r
\n" ); document.write( "\n" ); document.write( "Given: \"3%5Ex=40\"
\n" ); document.write( "Take the log of both sides
\n" ); document.write( "\"log%283%5Ex%29+=+log%2840%29\"
\n" ); document.write( "When using logs, if the term inside parens is raised to a power, then your can 'bring the power down' as a multiplier.
\n" ); document.write( "\"x+%2A+log%283%29+=+log%2840%29+\"
\n" ); document.write( "Now get out your handy calculator and find log(3) and log(40)
\n" ); document.write( "\"x+%2A+%280.47712%29+=+1.602\"
\n" ); document.write( "Now solve for x as a one step algebra simplification
\n" ); document.write( "\"x+=+3.3576\"\r
\n" ); document.write( "\n" ); document.write( "Finally, check your answer using a calculator. Does 3^3.3576 = 40? Close enough!\r
\n" ); document.write( "\n" ); document.write( "For the second problem, use logs again. Except this time, use natural log (ln)
\n" ); document.write( "Given: \"e%5E%280.04t%29=1500\"
\n" ); document.write( "Take the ln of both sides
\n" ); document.write( "\"ln%28e%5E%280.04t%29%29+=+ln%281500%29+\"
\n" ); document.write( "The ln of a power of e, it just the power.
\n" ); document.write( "\"0.04t+=+ln%281500%29+\"
\n" ); document.write( "Whip out your calculator and find ln(1500) (somebody help that man!)
\n" ); document.write( "\"0.04t+=+7.313\"
\n" ); document.write( "\"+t+=+182.83\"\r
\n" ); document.write( "\n" ); document.write( "Check your answer using the calculator. Does it check out? You bet it does,\r
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