document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143132>Question 143132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On the first day of school, the percentage of boys in a particular class is 60%.  During the school year, six girls move away, and are replaced in the class by six boys; this makes the class roster 75% boys.  Find the number of boys and girls in the class on the first day of school.\r<BR>\n" );
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document.write( "Any help with this word problem would be appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104194 by </B><A HREF=/tutors/aboutme.mpl?userid=pcsp_kumat><B>pcsp_kumat(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pcsp_kumat><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> no. of boys on first day=24<BR>\n" );
document.write( "no.of girls on first day=16<BR>\n" );
document.write( "total no. of students=40\r<BR>\n" );
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document.write( "solution:<BR>\n" );
document.write( "let total no. of students on first day be=x<BR>\n" );
document.write( "no.of boys will be=60% of x<BR>\n" );
document.write( "                  =60*x/100<BR>\n" );
document.write( "                  =3x/5<BR>\n" );
document.write( "no.of boys after changes=75%  [as no. of students remain same ]<BR>\n" );
document.write( "                        =75%of x<BR>\n" );
document.write( "                        =75*x/100<BR>\n" );
document.write( "                        =3x/4<BR>\n" );
document.write( "changes in boys=+6students<BR>\n" );
document.write( "  \r<BR>\n" );
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document.write( "so [on first day]+[changes]=[after changes]<BR>\n" );
document.write( "  =3x/5 +6 =3x/4<BR>\n" );
document.write( "  =[3x+30]/5 =3x/4              [then cross multiplication]<BR>\n" );
document.write( "  =12x+120=15x                  [transposing]<BR>\n" );
document.write( "  =120=15x -12x<BR>\n" );
document.write( "  =3x =120<BR>\n" );
document.write( "  =x =40\r<BR>\n" );
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document.write( "on first day [boys]=60%of40=24<BR>\n" );
document.write( "  remaining[girls] =40% of 40 =16 </SPAN>\n" );
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