document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143198>Question 143198</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321206002/algebrahomeworkh>Survey of Math w/ Apllications</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Could you help me with this px\r<BR>\n" );
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document.write( "7. (3 pts)  Set K contains 30 elements, set J contains 46 elements, and 11 elements are common to both sets. Find n ( K U J).  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104186 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If K has 30 elements and 11 of them are in common with J, then K has 30 - 11 = 19 elements that are NOT in common with J.  Likewise, J has 35 elements that are NOT in common with K.\r<BR>\n" );
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document.write( "The union of K and J consists of the elements of K not in common with J plus the elements of J not in common with K plus the elements that are common to both, so n = 19 + 35 + 11 = 65.\r<BR>\n" );
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document.write( "Another way to look at it is to say K has 30 elements and J has 46 elements and the sum is 76, but since they have 11 elements in common, adding the number of elements in the 2 sets means that you have counted 11 elements twice, so the number of elements in the union is 76 minus 11 = 65.  This method works fine for two sets, but gets horribly complicated when you try to figure the union of 3 or more sets, therefore the first method is a better general solution to this type of problem.\r<BR>\n" );
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document.write( "Super Double Plus Extra Credit: Find m(K&#8745;J) </SPAN>\n" );
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