document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143190>Question 143190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help in solving the following, I have no idea where to start.  <BR>\n" );
document.write( "The area of a square is 81 cm^2.  If the same amount is added to one dimenstion and removed from the other, the resulting rectangle has an area of 9cm^2 less than the area of the original square.  How much is added and subtracted.\r<BR>\n" );
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document.write( "Thank you so much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104183 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amt. added and subtracted.<BR>\n" );
document.write( "(9+x)(9-x)=72<BR>\n" );
document.write( "81-x^2=72<BR>\n" );
document.write( "-x^2=-9<BR>\n" );
document.write( "x^2=9<BR>\n" );
document.write( "x=3<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "(9+3)(9-3)=72 true<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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