document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21562>Question 21562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you show me how to solve this problem using algebra? The length of the rectangle is 3 cm more than twice the width. The perimeter is 60 cm. What is the length and width of this rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10416 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lenth = 2x+3<BR>\n" );
document.write( "width=x<BR>\n" );
document.write( "2(x+2x+3)=60<BR>\n" );
document.write( "6x+6=60<BR>\n" );
document.write( "6x=54<BR>\n" );
document.write( "x=9<BR>\n" );
document.write( "2(9)+3=21<BR>\n" );
document.write( "Hence, thw width is 9cm and the length is 21 cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );