document.write( "Question 143174This question is from textbook
\n" ); document.write( ": the area of a rectangular parcel of land is 720 sq. meters. the length of the land is 4 meters less than twice the width.
\n" ); document.write( "a. write an equation than can be used to find the dimensions of the land.
\n" ); document.write( "(i think i have this- 720=(2w-4)w)
\n" ); document.write( "b.solve the equation in part a. to find the dimensions of the land
\n" ); document.write( "Note: i already have the answer(l=36,w=20), i just don't know how to solve the equation)
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Algebra.Com's Answer #104156 by rapaljer(4671)\"\" \"About 
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Multiply out the parentheses. Since it's quadratic, you have to set it equal to zero:\r
\n" ); document.write( "\n" ); document.write( "720=(2w-4)w
\n" ); document.write( "720=2w^2 - 4w
\n" ); document.write( "0=2w^2 -4w -720\r
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\n" ); document.write( "\n" ); document.write( "Factor completely, beginning with the common factor of 2:
\n" ); document.write( "0=2(w^2 -2w-360)\r
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\n" ); document.write( "\n" ); document.write( "Factor the trinomial:
\n" ); document.write( "0=2(w+18)(w-20)\r
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\n" ); document.write( "\n" ); document.write( "w=-18 or w=20\r
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\n" ); document.write( "\n" ); document.write( "Reject the negative answer since a width cannot be negative.
\n" ); document.write( "So, w=20 meters
\n" ); document.write( "2w-4=2(20)-4=40-4=36 meters\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "Area = W*L
\n" ); document.write( "Area = 20*36=720 square meters\r
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\n" ); document.write( "\n" ); document.write( "R^2
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