document.write( "Question 143133: An express and local train leaves Allen's point at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train. i came up with 75 mph for the express and 58 for the local, but this doesn't seem right.\r
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Algebra.Com's Answer #104150 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
AT LEAST YOU TRIED!!!
\n" ); document.write( "ACTUALLY YOU CAN CHECK YOUR ANSWER, AS FOLLOWS:\r
\n" ); document.write( "\n" ); document.write( "TIME IT TOOK LOCAL=50/58= 0.862 HR
\n" ); document.write( "TIME IT TOOK EXPRESS=50/75=0.66667 HR
\n" ); document.write( "THERE SHOULD BE AN HOURS DIFFERENCE AND THERE'S NOT\r
\n" ); document.write( "\n" ); document.write( "LOOK AT THIS APPROACH:\r
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\n" ); document.write( "\n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let r= rate of the local
\n" ); document.write( "then 2r=rate of the express
\n" ); document.write( "Time it tool local to make the trip=50/r
\n" ); document.write( "Time it tool express to make the trip=50/2r\r
\n" ); document.write( "\n" ); document.write( "Now we are told that the express arrives 1 hour ahead of the local, so:\r
\n" ); document.write( "\n" ); document.write( "50/r -1 =50/2r multiply each term by 2r\r
\n" ); document.write( "\n" ); document.write( "50*2-2r=50 or\r
\n" ); document.write( "\n" ); document.write( "100-2r=50 subtract 100 from each side\r
\n" ); document.write( "\n" ); document.write( "100-100-2r=50-100 collect like terms\r
\n" ); document.write( "\n" ); document.write( "-2r=-50 divide each side by -2\r
\n" ); document.write( "\n" ); document.write( "r=25 mph------------------------------speed of local\r
\n" ); document.write( "\n" ); document.write( "2r=2*25=50 mph----------------------------speed of the express\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "time it took local=50/25=2hrs
\n" ); document.write( "Local arrived at 5 PM
\n" ); document.write( "time it took express =50/50=1hr\r
\n" ); document.write( "\n" ); document.write( "express arrives at 4 PM\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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