document.write( "Question 143128: Walt made an extra $9000 last year from a part-time job. He invested part of the money at a 9% annual rate of interest, and the rest at an 8% annual rate of interest. At the end of the year, he made a total of $770 in interest. How much was invested at 8%? Any help would be appreciated. Thank you very, very much. \n" ); document.write( "
Algebra.Com's Answer #104141 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
.09x+.08(9000-x)=770
\n" ); document.write( ".09x+720-.08x=770
\n" ); document.write( ".01x=770-720
\n" ); document.write( ".01x=50
\n" ); document.write( "x=50/.01
\n" ); document.write( "x=5000 is the amount invested @ 9%
\n" ); document.write( "9000-5000=4000 is the amount invested @ 8%
\n" ); document.write( "proof:
\n" ); document.write( ".09*5000+.08*4000=770
\n" ); document.write( "450+320=770
\n" ); document.write( "770=770
\n" ); document.write( "
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