document.write( "Question 143128: Walt made an extra $9000 last year from a part-time job. He invested part of the money at a 9% annual rate of interest, and the rest at an 8% annual rate of interest. At the end of the year, he made a total of $770 in interest. How much was invested at 8%? Any help would be appreciated. Thank you very, very much. \n" ); document.write( "
Algebra.Com's Answer #104141 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .09x+.08(9000-x)=770 \n" ); document.write( ".09x+720-.08x=770 \n" ); document.write( ".01x=770-720 \n" ); document.write( ".01x=50 \n" ); document.write( "x=50/.01 \n" ); document.write( "x=5000 is the amount invested @ 9% \n" ); document.write( "9000-5000=4000 is the amount invested @ 8% \n" ); document.write( "proof: \n" ); document.write( ".09*5000+.08*4000=770 \n" ); document.write( "450+320=770 \n" ); document.write( "770=770 \n" ); document.write( " \n" ); document.write( " |