document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=143108>Question 143108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please Help me find the solution of this equation by using the elimination(linear combination0 method.I already got x which is 2.4 put I can not get y.\r<BR>\n" );
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document.write( "3x-2y=5<BR>\n" );
document.write( "2x+2y=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #104128 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=104128\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-2y=5<BR>\n" );
document.write( "2x+2y=6 now add these 2 equations.<BR>\n" );
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document.write( "5x=11<BR>\n" );
document.write( "x=11/5 answer.<BR>\n" );
document.write( "3*11/5-2y=5<BR>\n" );
document.write( "33/5-2y=5<BR>\n" );
document.write( "-2y=5-33/5<BR>\n" );
document.write( "-2y=(25-33)/5<BR>\n" );
document.write( "-2y=-8/5<BR>\n" );
document.write( "y=(-8/5)/-2<BR>\n" );
document.write( "y=(-8/5)(-1/2)<BR>\n" );
document.write( "y=8/10 <BR>\n" );
document.write( "y=4/5 answer.<BR>\n" );
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