document.write( "Question 143075: PLEASE HELP
\n" ); document.write( "Eliminating the parameter in the parametric equations x = 5-3t, y = 2+t yields the equation
\n" ); document.write( "a. y = -x + (11/3)
\n" ); document.write( "b y = (-x/3) + (11/3)
\n" ); document.write( "c. y = (-x/3) + (1/3)
\n" ); document.write( "d. y = (-x/3) - (1/3)
\n" ); document.write( "THANK YOU
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Algebra.Com's Answer #104108 by stanbon(75887)\"\" \"About 
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Eliminating the parameter in the parametric equations x = 5-3t, y = 2+t yields the equation
\n" ); document.write( "a. y = -x + (11/3)
\n" ); document.write( "b y = (-x/3) + (11/3)
\n" ); document.write( "c. y = (-x/3) + (1/3)
\n" ); document.write( "d. y = (-x/3) - (1/3)
\n" ); document.write( "---------------------
\n" ); document.write( "Solve each equation for \"t\":
\n" ); document.write( "t = (5-x)/3
\n" ); document.write( "t = y-2
\n" ); document.write( "-------------
\n" ); document.write( "Equate the expressions:
\n" ); document.write( "y-2 = (5-x)/3
\n" ); document.write( "y = (-1/3)x + 5/3 + 2
\n" ); document.write( "y = (-1/3)x + (11/3)
\n" ); document.write( "Ans: b
\n" ); document.write( "===================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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