document.write( "Question 143075: PLEASE HELP
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document.write( "Eliminating the parameter in the parametric equations x = 5-3t, y = 2+t yields the equation
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document.write( "a. y = -x + (11/3)
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document.write( "b y = (-x/3) + (11/3)
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document.write( "c. y = (-x/3) + (1/3)
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document.write( "d. y = (-x/3) - (1/3)
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document.write( "THANK YOU
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document.write( "
Algebra.Com's Answer #104108 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Eliminating the parameter in the parametric equations x = 5-3t, y = 2+t yields the equation \n" ); document.write( "a. y = -x + (11/3) \n" ); document.write( "b y = (-x/3) + (11/3) \n" ); document.write( "c. y = (-x/3) + (1/3) \n" ); document.write( "d. y = (-x/3) - (1/3) \n" ); document.write( "--------------------- \n" ); document.write( "Solve each equation for \"t\": \n" ); document.write( "t = (5-x)/3 \n" ); document.write( "t = y-2 \n" ); document.write( "------------- \n" ); document.write( "Equate the expressions: \n" ); document.write( "y-2 = (5-x)/3 \n" ); document.write( "y = (-1/3)x + 5/3 + 2 \n" ); document.write( "y = (-1/3)x + (11/3) \n" ); document.write( "Ans: b \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |