document.write( "Question 143029: Find all values of x in the interval 0 degrees is less than or equal to x which is less than 360 degrees that satisfy the equation 3cosx+sin2x=0. \n" ); document.write( "
Algebra.Com's Answer #104084 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find all values of x in the interval 0 degrees is less than or equal to x which is less than 360 degrees that satisfy the equation 3cosx+sin2x=0. \n" ); document.write( "----------------- \n" ); document.write( "3cosx + sin2x = 0 \n" ); document.write( "3cosx + 2sinxcosx = 0 \n" ); document.write( "Factor: \n" ); document.write( "cosx[3 + 2sinx] = 0 \n" ); document.write( "cosx = 0 or sinx = -3/2 \n" ); document.write( "Solutions in 0 <= x <= 360 \n" ); document.write( "If cos=0, x = 0 or 270 \n" ); document.write( "-------- \n" ); document.write( "sinx cannot equal -3/2 \n" ); document.write( "---------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |