document.write( "Question 143029: Find all values of x in the interval 0 degrees is less than or equal to x which is less than 360 degrees that satisfy the equation 3cosx+sin2x=0. \n" ); document.write( "
Algebra.Com's Answer #104084 by stanbon(75887)\"\" \"About 
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Find all values of x in the interval 0 degrees is less than or equal to x which is less than 360 degrees that satisfy the equation 3cosx+sin2x=0.
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\n" ); document.write( "3cosx + sin2x = 0
\n" ); document.write( "3cosx + 2sinxcosx = 0
\n" ); document.write( "Factor:
\n" ); document.write( "cosx[3 + 2sinx] = 0
\n" ); document.write( "cosx = 0 or sinx = -3/2
\n" ); document.write( "Solutions in 0 <= x <= 360
\n" ); document.write( "If cos=0, x = 0 or 270
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\n" ); document.write( "sinx cannot equal -3/2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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